my question simple. here scenario:
- i have 1 result dataset[named="resultds" typed="mydataset"] , 1 datatable[mydt] inside.
- in datatable, have 10 rows, each row has 3 columns [column1,column2,column3]
- on aspx page, have 30 drowdownlists waiting above data
the data inside datatable be:
column1 | column2 | column3
method1 | 100 | 0.5
method2 | 125 | 0.75
method3 | 80 | 0.4
. . .
method30 | 200 | 1
currently, used simplest way binding data. like:
ddl1.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[0]).column1; ddl2.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[0]).column2; ddl3.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[0]).column3; ddl4.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[1]).column1; ddl5.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[1]).column2; ddl6.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[1]).column3; . . . ddl30.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[9]).column3;
is there way bind data ddl easier current method?
thank you.
vcha
assuming last line in code has rows[9]
you can try doing in loop
for (int i=0; i<30; i++) { dropdownlist ddl = (dropdownlist) findcontrol("ddl"+(i+1)); switch (i % 3) { case 0: ddl.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[i/3]).column1; break; case 1: ddl.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[i/3]).column2; break; case 2: ddl.selectedvalue = ((mydataset.mydtrow)resultds.mydt.rows[i/3]).column3; break; } }
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