public class simple { public static void main(string[] args) { try { system.out.print("hello "); throwit(); } catch (exception re) { system.out.print("caught "); } } public static void throwit(){ // line number 11 throw new exception(); // line number 12 } }
why give me compile error in line number 12. if use throws exception line number 11 work fine. if throw subclass of exception(in line number 12) work properly... why so?...
i want know happen in side(how compiler shows error this)?
you have method there throwing checked exception, method signature doesn't specify able that. checked exceptions have declared in method signature, , explicitly handled try/catch blocks or rethrowing; that's definition of checked exception is. :)
this line:
public static void throwit()
should be
public static void throwit() throws exception
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